Dallas Fort Worth Airport will have free Wi-Fi for all thanks to AT&T

6
Dallas Fort Worth Airport will have free Wi-Fi for all thanks to AT&T
The next time you and all of your mobile devices trek through Dallas/Fort Worth (DFW) International Airport, you won’t have to worry about using up your data quota or paying Wi-Fi access fees. The DFW Board of Directors have approved a deal that will allow AT&T to provide free Wi-Fi access at all five terminals to all travelers.

Slated to launch in September, the service will require customers to view a 30-second advertisement for every 40 minutes of usage. It will cover more than 6 million square feet of space and be accessible by the over 57 million travelers that pass through DFW every year.

In addition to offering free service, AT&T plans on upgrading the current network by increasing speeds and covering an even wider area that will eventually encompass parking garages and gate accessible areas.

Recommended For You
"The deal to provide AT&T Wi-Fi access across DFW Airport is a tremendous leap forward for our passengers in terms of speed and coverage area, and it answers one of our most frequently-requested customer enhancements," said Jeff Fegan, CEO of DFW International Airport.  "We are very pleased to join with AT&T, our Dallas-based neighbor, to provide world-class and complimentary Wi-Fi service for everyone who visits DFW."

Overall, a 30-second ad for 40 minutes of service seems very, very reasonable. What do you think? Is this a fair advertisement trade off for free service? Would you like to see service like this offered in more places?

source: PRNewsWire

Get Visible as low as $20/mo for 1 year. Limited time offer with code: FRESHSTART

$20 /mo
$25
$5 off (20%)
Offer Ends 6.1.2026 at 11.59pm ET. New members get $5/mo off the $25/mg Visible plan, $35/mo Visible+ plan, or $45/mo Visible+ Pro plan for the first 12 months. Promo code FRESHSTART required at checkout.
Buy at Visible
Recommended For You
COMMENTS (6)
Latest Discussions
by ECPirate37 • 1
by menooch18 • 2